document.write( "Question 140867: Tutors can you help me?*\r
\n" ); document.write( "\n" ); document.write( "find the center and the radius of the circle given by x^2+8x+y^2+6y-24=0
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Algebra.Com's Answer #102504 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "\"x%5E2%2B8x%2By%5E2%2B6y-24=0\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B8x%2By%5E2%2B6y=%2B24\" Add \"24\" to both sides\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B4%29%5E2-16%2By%5E2%2B6y=%2B24\" Complete the square for the x terms\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B4%29%5E2-16%2B%28y%2B3%29%5E2-9=%2B24\" Complete the square for the y terms\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B4%29%5E2%2B%28y%2B3%29%5E2-25=%2B24\" Combine like terms\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B4%29%5E2%2B%28y%2B3%29%5E2=%2B24%2B25\" Add \"25\" to both sides\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B4%29%5E2%2B%28y%2B3%29%5E2=49\" Combine like terms\r
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\n" ); document.write( "\n" ); document.write( "Notice how the equation is now in the form \"%28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2\". This means that this conic section is a circle where (h,k) is the center and \"r\" is the radius.\r
\n" ); document.write( "\n" ); document.write( "So the circle has these properties:\r
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\n" ); document.write( "\n" ); document.write( "CENTER: (-4,-3)\r
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\n" ); document.write( "\n" ); document.write( "Radius: \"r=sqrt%2849%29=7\"
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