document.write( "Question 140853: A clothing manufacturer has 100 m of sill and 180 of wool. To make a suite it requires 2m of silk adn 3m of wool, and to make a dress 1m of silk and 2m of wool. If the profit on the suit is $108 and the profit on the dress is $60, how many suits and dressed should be madeto maximize the profit?\r
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document.write( "I started something but it's wrong. Please help!\r
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document.write( "2x+1y=108
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document.write( "x+2y= 60\r
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document.write( "Profit = 108x+60y\r
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Algebra.Com's Answer #102500 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A clothing manufacturer has 100 m of silk and 180 m of wool. \n" ); document.write( "To make a suit it requires 2m of silk and 3m of wool, \n" ); document.write( "to make a dress 1m of silk and 2m of wool. \n" ); document.write( "If the profit on the suit is $108 and the profit on the dress is $60, \n" ); document.write( "how many suits and dresses should be made to maximize the profit? \n" ); document.write( "------------------------- \n" ); document.write( "Let # of suits be \"s\"; Let # of dresses be \"d\": \n" ); document.write( "Profit = 108s + 60d \n" ); document.write( "--------------------\r \n" ); document.write( "\n" ); document.write( "Silk: 2s + d <= 100 \n" ); document.write( "Wool: 3s +2d <= 180 \n" ); document.write( "---------------------- \n" ); document.write( "Solve both for d and graph them: \n" ); document.write( "d <= -2s + 100 \n" ); document.write( "d <= (-3/2)s + 90 \n" ); document.write( "----------------------- \n" ); document.write( " \n" ); document.write( "----------------------- \n" ); document.write( "Find the coordinates of the enclosed polygon and test the \n" ); document.write( "coordinates in the Profit equation to determine the maximum. \n" ); document.write( "----------------------- \n" ); document.write( "Coordinates: (20,60), (0,0) , (0,90), (50,0) \n" ); document.write( "----------------------- \n" ); document.write( "Determining maximum Profit: \n" ); document.write( "Profit = 108s + 60d \n" ); document.write( "(20,60): P = 108*20 + 60*60 = 5760 \n" ); document.write( "(0,90): P = 90*60 = 5400 \n" ); document.write( "(50,0): p = 50*108 = 5400 \n" ); document.write( "------------------------------ \n" ); document.write( "Maximum profit comes when 20 dresses and 60 suits are produced \n" ); document.write( "================================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |