document.write( "Question 140846: please help. write the equation of the root \r
\n" ); document.write( "\n" ); document.write( "6,-2/3 thanks for your help
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Algebra.Com's Answer #102496 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Since \"6\" and \"-2%2F3\" are given zeros this means that:\r
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\n" ); document.write( "\n" ); document.write( "\"x=6\" and \"x=-2%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "Get all terms to the left side in each case\r
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\n" ); document.write( "\n" ); document.write( "\"x-6=0\" and \"3x%2B2=0\"\r
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\n" ); document.write( "\n" ); document.write( "Now use the zero product property in reverse to join the factors.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-6%29%283x%2B2%29=0\"\r
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\n" ); document.write( "\n" ); document.write( "Expand and multiply\r
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\n" ); document.write( "\n" ); document.write( "\"3%2Ax%5E2-16%2Ax-12=0\"\r
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\n" ); document.write( "\n" ); document.write( "-------------------------------------------\r
\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the polynomial with roots of \"6\" and \"-2%2F3\" is\r
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\n" ); document.write( "\n" ); document.write( "\"3%2Ax%5E2-16%2Ax-12\"\r
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\n" ); document.write( "\n" ); document.write( "Notice how if we graph \"y=3%2Ax%5E2-16%2Ax-12\", we can visually verify our answer\r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C+3%2Ax%5E2-16%2Ax-12+%29+\" Graph of \"y=3%2Ax%5E2-16%2Ax-12\" with roots of \"x=6\" and \"x=-2%2F3\"
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