document.write( "Question 140800: The area of a rectangle is 24 square meters.Find the length and width of the rectangle if its length is 2 meters greater than its width. Use an equation and the formula---->area of the rectangle=(width)(length). \n" ); document.write( "
Algebra.Com's Answer #102495 by jojo14344(1513)![]() ![]() ![]() You can put this solution on YOUR website! Absolutely! \n" ); document.write( "First, we know that Area(rect)=(Length)(Width)--- mark eqn. 1 \n" ); document.write( "And we know too that the Length is 2meters greater than width, \n" ); document.write( "so L= W+2, right?---- mark eqn. 2 Then substitute this value of L in eqn 1, \n" ); document.write( "A=(W+2)(W) \n" ); document.write( "24= W^2+2W \n" ); document.write( "W^2+2W-24=0 \n" ); document.write( "(W+6)(W-4)=0 \n" ); document.write( "It has 2 values, \n" ); document.write( "W=-6, cannot be because there's no negative measurement for rect. right? \n" ); document.write( "The other, W=4, perfect! This is the width. \n" ); document.write( "Go back eqn 2 to get L= W+2=4+2 \n" ); document.write( "L=6 meters \n" ); document.write( "In doubt? Go back eqn 1 to check, \n" ); document.write( "A=LW \n" ); document.write( "24=6*4 \n" ); document.write( "24sq m = 24sq m cool! \n" ); document.write( "Thank you, \n" ); document.write( "Jojo\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |