document.write( "Question 140800: The area of a rectangle is 24 square meters.Find the length and width of the rectangle if its length is 2 meters greater than its width. Use an equation and the formula---->area of the rectangle=(width)(length). \n" ); document.write( "
Algebra.Com's Answer #102495 by jojo14344(1513)\"\" \"About 
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Absolutely!
\n" ); document.write( "First, we know that Area(rect)=(Length)(Width)--- mark eqn. 1
\n" ); document.write( "And we know too that the Length is 2meters greater than width,
\n" ); document.write( "so L= W+2, right?---- mark eqn. 2 Then substitute this value of L in eqn 1,
\n" ); document.write( "A=(W+2)(W)
\n" ); document.write( "24= W^2+2W
\n" ); document.write( "W^2+2W-24=0
\n" ); document.write( "(W+6)(W-4)=0
\n" ); document.write( "It has 2 values,
\n" ); document.write( "W=-6, cannot be because there's no negative measurement for rect. right?
\n" ); document.write( "The other, W=4, perfect! This is the width.
\n" ); document.write( "Go back eqn 2 to get L= W+2=4+2
\n" ); document.write( "L=6 meters
\n" ); document.write( "In doubt? Go back eqn 1 to check,
\n" ); document.write( "A=LW
\n" ); document.write( "24=6*4
\n" ); document.write( "24sq m = 24sq m cool!
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo\r
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