document.write( "Question 140835: Can someone help me calculate the 20th partial sum for 6400,1600,400,100,25...? \n" ); document.write( "
Algebra.Com's Answer #102478 by stanbon(75887)\"\" \"About 
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calculate the 20th partial sum for 6400,1600,400,100,25...?
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\n" ); document.write( "You have a geometric sequence with r = (1/4), and a(1)=6400.
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\n" ); document.write( "S(20) = 6400[r^n -1]/[r-1]
\n" ); document.write( "S(20) = 6400[(1/4)^20 -1]/[-3/4]
\n" ); document.write( "S(20) = 8533.3333...
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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