document.write( "Question 140794: find three consecutive odd integers whose sum is 33 \n" ); document.write( "
Algebra.Com's Answer #102471 by ptaylor(2198)\"\" \"About 
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Let n=first
\n" ); document.write( "Then n+2=second
\n" ); document.write( "and n+4=third\r
\n" ); document.write( "\n" ); document.write( "n+n+2+n+4=33 simplify\r
\n" ); document.write( "\n" ); document.write( "3n+6=33 subtract 6 from each side\r
\n" ); document.write( "\n" ); document.write( "3n+6-6=33-6\r
\n" ); document.write( "\n" ); document.write( "3n=27 divide each side by 3
\n" ); document.write( "n=9------------------------------------first integer
\n" ); document.write( "n+2=9+2=11----------------------------second integer
\n" ); document.write( "n+4=9+4=13-------------------------------third integer\r
\n" ); document.write( "\n" ); document.write( "CK\r
\n" ); document.write( "\n" ); document.write( "9+11+13=33
\n" ); document.write( "33=33\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor
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