document.write( "Question 140752: zelma is eighteen years older than her son. she was three times as old as he was one year ago. how old are they now? \n" ); document.write( "
Algebra.Com's Answer #102470 by ptaylor(2198)\"\" \"About 
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Let x=her son's age now
\n" ); document.write( "then x-1=her son's age one year ago\r
\n" ); document.write( "\n" ); document.write( "x+18=Zelma's age now
\n" ); document.write( "and x+17=Zelma's age 1 year ago\r
\n" ); document.write( "\n" ); document.write( "Now we are told the following:
\n" ); document.write( "------she was three times as old as he was (her son) one year ago-----\r
\n" ); document.write( "\n" ); document.write( "x+17=3(x-1) get rid of parens (distributive)\r
\n" ); document.write( "\n" ); document.write( "x+17=3x-3 subtract 3x and also 17 from each side\r
\n" ); document.write( "\n" ); document.write( "x+17-17-3x=3x-3x-3-17 collect like terms\r
\n" ); document.write( "\n" ); document.write( "-2x=-20 divide each side by -2
\n" ); document.write( "x=10-------------------------------------her son's age now\r
\n" ); document.write( "\n" ); document.write( "x+18=10+18=28---------------------------------Zelma's age now\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "-----------zelma is eighteen years older than her son-----
\n" ); document.write( "10+18=28
\n" ); document.write( "28=28
\n" ); document.write( "------she was three times as old as he was (her son) one year ago-----\r
\n" ); document.write( "\n" ); document.write( "10+17=3(10-1)
\n" ); document.write( "27=3*9
\n" ); document.write( "27=27\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor\r
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