document.write( "Question 140752: zelma is eighteen years older than her son. she was three times as old as he was one year ago. how old are they now? \n" ); document.write( "
Algebra.Com's Answer #102470 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Let x=her son's age now \n" ); document.write( "then x-1=her son's age one year ago\r \n" ); document.write( "\n" ); document.write( "x+18=Zelma's age now \n" ); document.write( "and x+17=Zelma's age 1 year ago\r \n" ); document.write( "\n" ); document.write( "Now we are told the following: \n" ); document.write( "------she was three times as old as he was (her son) one year ago-----\r \n" ); document.write( "\n" ); document.write( "x+17=3(x-1) get rid of parens (distributive)\r \n" ); document.write( "\n" ); document.write( "x+17=3x-3 subtract 3x and also 17 from each side\r \n" ); document.write( "\n" ); document.write( "x+17-17-3x=3x-3x-3-17 collect like terms\r \n" ); document.write( "\n" ); document.write( "-2x=-20 divide each side by -2 \n" ); document.write( "x=10-------------------------------------her son's age now\r \n" ); document.write( "\n" ); document.write( "x+18=10+18=28---------------------------------Zelma's age now\r \n" ); document.write( "\n" ); document.write( "CK \n" ); document.write( "-----------zelma is eighteen years older than her son----- \n" ); document.write( "10+18=28 \n" ); document.write( "28=28 \n" ); document.write( "------she was three times as old as he was (her son) one year ago-----\r \n" ); document.write( "\n" ); document.write( "10+17=3(10-1) \n" ); document.write( "27=3*9 \n" ); document.write( "27=27\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |