document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=140771>Question 140771</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In drag racing, both vehicles begin at a dead stop, then accelerate through 1/4 mi.  Let us say, for the sake of discussion, that our two vehicles are not quite matched in power.  That is, vehicle A can accelerate from 0 mph to 60 mph in 5 secs., whereas the vehicle B can accelerate from 0 mph to 60 mph in 4 secs.  <BR>\n" );
document.write( " <BR>\n" );
document.write( "DQ 3:    How would you determine the time, t, for the fastest vehicle to traverse 1/4 mi.?\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #102463 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=102463\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> for constant acceleration __ distance equals one half times the acceleration times the square of the time __ d=.5at^2\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "2d=at^2 __ 2d/a=t^2 __ sqrt(2d/a)=t\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "60mph=60mph(5280ft/mi)/(3600sec/hr)=88ft/sec<BR>\n" );
document.write( "__ a=60mph/4sec=88ft/sec/4sec=22ft/sec^2\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "t=sqrt(2*1320ft/22ft/sec^2)=sqrt(120sec^2)=slightly under 11sec </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );