document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=140755>Question 140755</A>: <I><SPAN STYLE=\"word-break: break-all;\"> can you help me with this problem? it is... the perimeter of a rectangle is 160ft. one fourth the length is the same as twice the width. find the dimension of the rectangle.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #102440 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=102440\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> PERIMETER=2L+2W<BR>\n" );
document.write( "L/4=2W<BR>\n" );
document.write( "L=8W<BR>\n" );
document.write( "160=2*8W+2W<BR>\n" );
document.write( "160=16W+2W<BR>\n" );
document.write( "160=18W<BR>\n" );
document.write( "W=160/18<BR>\n" );
document.write( "W=80/9 ANSWER FOR THE WIDTH.<BR>\n" );
document.write( "L=8*80/9<BR>\n" );
document.write( "L=640/9 ANSWER FOR THE LENGTH.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "160=2*80/9+2*640/9<BR>\n" );
document.write( "160=160/9+1280/9<BR>\n" );
document.write( "160=1440/9<BR>\n" );
document.write( "160=160\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );