document.write( "Question 140743: please help!! use the quadratic equation -b+ (tiny line under the plus sign) sqrt(b^2-4ac)/2a to find the roots of the equation x^2-3x+2=0 thanks for your help.I really appreciate all ya'll do. \n" ); document.write( "
Algebra.Com's Answer #102436 by c-dubb swimmer(3)\"\" \"About 
You can put this solution on YOUR website!
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B-3x%2B2+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-3%29%5E2-4%2A1%2A2=1\".
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\n" ); document.write( " Discriminant d=1 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--3%2B-sqrt%28+1+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%28-3%29%2Bsqrt%28+1+%29%29%2F2%5C1+=+2\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%28-3%29-sqrt%28+1+%29%29%2F2%5C1+=+1\"
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\n" ); document.write( " Quadratic expression \"1x%5E2%2B-3x%2B2\" can be factored:
\n" ); document.write( " \"1x%5E2%2B-3x%2B2+=+1%28x-2%29%2A%28x-1%29\"
\n" ); document.write( " Again, the answer is: 2, 1.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-3%2Ax%2B2+%29\"
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