document.write( "Question 140735: The sum of the squares of two consecutive negative integers is 100. Find the integers. (I got the answer but i don't know how to solve it, I did guess and check) \n" ); document.write( "

Algebra.Com's Answer #102425 by checkley77(12844) $\"\"$ $\"About$

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thnks but I got 8 and 13
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\n" ); document.write( "Can't be the correct answers because they are not consecutive integers and they don't work in the proof:
\n" ); document.write( "8^2+13^2=64+169=233 not 100.
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\n" ); document.write( "(-x)^2+(-x+1)^2=100
\n" ); document.write( "x^2+x^2-2x+1=100
\n" ); document.write( "2x^2-2x+1-100=0
\n" ); document.write( "x^2-2x-99=0
\n" ); document.write( "using the quadratic equation $\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"$ we get:
\n" ); document.write( "x=(2+-sqrt[-2^2-4*2*-99])/2*2
\n" ); document.write( "x=(2+-sqrt[4+792)/4
\n" ); document.write( "x=(2+-sqrt796)/4
\n" ); document.write( "x=(2+-28.2)/4
\n" ); document.write( "x=(2-28.2)/4
\n" ); document.write( "x=-26.2/4
\n" ); document.write( "x=-6.55 answer.
\n" ); document.write( "-6.55+1=-5.55 answer. \n" ); document.write( "

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