document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=140708>Question 140708</A>: <I><SPAN STYLE=\"word-break: break-all;\"> SOLVE USING THE SQUARE ROOT PROPERTY: <BR>\n" );
document.write( "-2(x-2)^2= -6<BR>\n" );
document.write( "HERE I'M CONFUSED ON WHAT ALL TO SQUARE??? DO I SQUARE EVERTHING ON THE RIGHT OR WHAT PLEASE HELP AS SOON AS YOU CAN... TAHNKS </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #102423 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=102423\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -2(x-2)^2=-6<BR>\n" );
document.write( "divide both sides by -2<BR>\n" );
document.write( "(x-2)^2=-6/-2<BR>\n" );
document.write( "(x-2)^2=3<BR>\n" );
document.write( "now take the square root of both sides<BR>\n" );
document.write( "x-2=sqrt3<BR>\n" );
document.write( "x=sqrt3+2<BR>\n" );
document.write( "x=1.73+2<BR>\n" );
document.write( "x=3.73 answer. <BR>\n" );
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