document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=21324>Question 21324</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A baker mixes cookies worth $0.95 per pound with cookies worth $1.70 per pound. How many of each kind must be used to produce a 45 pound mixture that sells for $1.25 a pound. I have a benchmark test tomorrow and i don't get how to set up the equations!! If you could tell me how, that would be great. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #10242 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=10242\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 0.95x+1.70(45-x)=1.25(45)<BR>\n" );
document.write( "0.95x+76.5-1.7x=56.25<BR>\n" );
document.write( "-0.75x=-20.25 (divide both sides by -0.75)<BR>\n" );
document.write( "x=27<BR>\n" );
document.write( "45-27=18\r<BR>\n" );
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document.write( "Hence 0.95 needs 27 pound mixture and the other needs 18 pounds of mixture </SPAN>\n" );
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