document.write( "Question 140728: SOLVE BY COMPETING THE SQUARE:
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document.write( "x^2-6x+12=0
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document.write( "PLEASE HELP... I KNOW HOW TO USE THE QUADRATIC FORMULA... BUT I DO NOT KNOW HOW TO DO THE COMPLETING THE SQUARE... \n" );
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Algebra.Com's Answer #102419 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! x^2-6x+12=0 \n" ); document.write( "FIRST REMIOVE THE 12 OVER TO THE RIGHT SIDE OF THE = SIGN. \n" ); document.write( "X^2-6X=12 \n" ); document.write( "NOW CALCULATE THE NUMBER TO COMPLETE THE SQUARE. \n" ); document.write( "(6/2)^2=3^2=9 WHICH IS THE MISSING TERM THAT MUST BE ADDED TO EACH SIDE OF THE EQUATION \n" ); document.write( "X^2-6X+9=12+9 \n" ); document.write( "(X-3)^2=21 \n" ); document.write( "TAKE THE SQUARE ROOT OF BOTH SIDES \n" ); document.write( "X-3=SQRT21 \n" ); document.write( "ADD 3 TO BOTH SIDES \n" ); document.write( "X=SQRT21+3 \n" ); document.write( "X=4.58+3 \n" ); document.write( "X=7.58 ANSWER. \n" ); document.write( " |