document.write( "Question 140728: SOLVE BY COMPETING THE SQUARE:
\n" ); document.write( "x^2-6x+12=0
\n" ); document.write( "PLEASE HELP... I KNOW HOW TO USE THE QUADRATIC FORMULA... BUT I DO NOT KNOW HOW TO DO THE COMPLETING THE SQUARE...
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Algebra.Com's Answer #102419 by checkley77(12844)\"\" \"About 
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x^2-6x+12=0
\n" ); document.write( "FIRST REMIOVE THE 12 OVER TO THE RIGHT SIDE OF THE = SIGN.
\n" ); document.write( "X^2-6X=12
\n" ); document.write( "NOW CALCULATE THE NUMBER TO COMPLETE THE SQUARE.
\n" ); document.write( "(6/2)^2=3^2=9 WHICH IS THE MISSING TERM THAT MUST BE ADDED TO EACH SIDE OF THE EQUATION
\n" ); document.write( "X^2-6X+9=12+9
\n" ); document.write( "(X-3)^2=21
\n" ); document.write( "TAKE THE SQUARE ROOT OF BOTH SIDES
\n" ); document.write( "X-3=SQRT21
\n" ); document.write( "ADD 3 TO BOTH SIDES
\n" ); document.write( "X=SQRT21+3
\n" ); document.write( "X=4.58+3
\n" ); document.write( "X=7.58 ANSWER.
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