document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=140723>Question 140723</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/9780073268620/algebrahomeworkh>Elementary and Intermediate Algebra</A><BR>\n" );
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document.write( "Winter Wheat. While finding the amount of seed needed to plant his three square wheat fields, Hank observed that the side of one field was 1 kilometer longer than the side of the smallest field and that the side of the largest field was 3 kilometers longer than the side of the smallest field. If the total area of the three fields is 38 square kilometers then what is the area of each field?\r<BR>\n" );
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document.write( "We have been using pythagorean theorem in some problems, but I'm not sure how to set this one up. Could you help me with this? Anne </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #102415 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=102415\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the area of each field is the side squared\r<BR>\n" );
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document.write( "let x=\"smallest field\"\r<BR>\n" );
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document.write( "\"the side of one field was 1 kilometer longer than the side of the smallest field\" __ x+1\r<BR>\n" );
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document.write( "\"the side of the largest field was 3 kilometers longer than the side of the smallest field\" __ x+3\r<BR>\n" );
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document.write( "\"the total area of the three fields is 38 square kilometers\" __ x^2+(x+1)^2+(x+3)^2=38\r<BR>\n" );
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document.write( "x^2+x^2+2x+1+x^2+6x+9=38 __ 3x^2+8x+10=38 __ 3x^2+8x-28=0 __ factoring __ (3x+14)(x-2)=0\r<BR>\n" );
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document.write( "3x+14=0 __ x=-14/3 __ negative value not realistic\r<BR>\n" );
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document.write( "x-2=0 __ x=2 </SPAN>\n" );
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