document.write( "Question 140699: How do i solve log64^8=x\r
\n" ); document.write( "\n" ); document.write( "The answer is 1/2 but how do you come about that answer?\r
\n" ); document.write( "\n" ); document.write( "Also log5^1/5=x & log7^square root of 7=x\r
\n" ); document.write( "\n" ); document.write( "These have me so confused.
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Algebra.Com's Answer #102402 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I'm assuming that the problem looks like this: \"log%2864%2C%288%29%29=x\"???\r
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\n" ); document.write( "\n" ); document.write( "\"log%2864%2C%288%29%29=x\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"log%2810%2C%288%29%29%2Flog%2810%2C%2864%29%29=x\" Rewrite the left side by using the change of base formula. Remember the change of base formula is \"log%28b%2C%28x%29%29=log%2810%2C%28x%29%29%2Flog%2810%2C%28b%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%2810%2C%288%29%29%2Flog%2810%2C%288%5E2%29%29=x\" Rewrite 64 as \"8%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%2810%2C%288%29%29%2F%282%2Alog%2810%2C%288%29%29%29=x\" Rewrite the denominator using the identity \"log%28b%2C%28x%5Ey%29%29=y%2Alog%28b%2C%28x%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"cross%28log%2810%2C%288%29%29%29%2F%282cross%28log%2810%2C%288%29%29%29%29=x\" Divide and cancel like terms\r
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\n" ); document.write( "\n" ); document.write( "\"1%2F2=x\" Simplify\r
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\n" ); document.write( "\n" ); document.write( "So the answer is \"x=1%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%285%2C%281%2F5%29%29=x\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"log%2810%2C%281%2F5%29%29%2Flog%2810%2C%285%29%29=x\" Rewrite the left side by using the change of base formula. \r
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\n" ); document.write( "\n" ); document.write( "\"log%2810%2C%281%2F5%29%29%2Flog%2810%2C%28%281%2F5%29%5E%28-1%29%29%29=x\" Rewrite 5 as \"%281%2F5%29%5E%28-1%29\". Notice how \"5=%281%2F5%29%5E%28-1%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%2810%2C%281%2F5%29%29%2F%28-1%2Alog%2810%2C%281%2F5%29%29%29=x\" Rewrite the denominator using the identity \"log%28b%2C%28x%5Ey%29%29=y%2Alog%28b%2C%28x%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"cross%28log%2810%2C%281%2F5%29%29%29%2F%28-1%2Across%28log%2810%2C%281%2F5%29%29%29%29=x\" Cancel like terms\r
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\n" ); document.write( "\n" ); document.write( "\"1%2F%28-1%29=x\" Simplify\r
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\n" ); document.write( "\n" ); document.write( "\"x=-1\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "So the answer is \"x=-1\" \r
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\n" ); document.write( "\n" ); document.write( "\"log%287%2C%28sqrt%287%29%29%29=x\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"log%287%2C%287%5E%281%2F2%29%29%29=x\" Rewrite \"sqrt%287%29\" as \"7%5E%281%2F2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%281%2F2%29%2Alog%287%2C%287%29%29=x\" Rewrite the expression using the identity \"log%28b%2C%28x%5Ey%29%29=y%2Alog%28b%2C%28x%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%281%2F2%29%2A1=x\" Take the log base 7 of 7 to get 1. In other words, \"log%287%2C%287%29%29=1\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=1%2F2\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "So the answer is \"x=1%2F2\"
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