document.write( "Question 140641: 3. To estimate animal populations, biologists count the total number of animals in a small section of a habitat. The total population of animals is directly proportional to the size of the habitat (in acres) polled. \r
\n" ); document.write( "\n" ); document.write( "a. Write an equation using only one variable that could be used to solve for the constant of variation k. \r
\n" ); document.write( "\n" ); document.write( "b. A biologist counted the number of white tail deer in a 100 acre parcel of land in a nature preserve and found 12 deer. Find the constant of variation k. \r
\n" ); document.write( "\n" ); document.write( "c. If the entire nature preserve is 2,500 acres, then what is the total white tail deer population in the preserve? Describe how you arrived at your answer. \r
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Algebra.Com's Answer #102354 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let p=# of animals and a=size of habitat\r
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\n" ); document.write( "\n" ); document.write( "So if the \"total population of animals is directly proportional to the size of the habitat\", this means that we have the equation\r
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\n" ); document.write( "\n" ); document.write( "\"p=k%2Aa\"\r
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\n" ); document.write( "\n" ); document.write( "b)\r
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\n" ); document.write( "\n" ); document.write( "In this case p=12 and a=100\r
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\n" ); document.write( "\n" ); document.write( "\"p=k%2Aa\" Start with the equation we found earlier\r
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\n" ); document.write( "\n" ); document.write( "\"12=k%2A100\" Plug in p=12 and a=100\r
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\n" ); document.write( "\n" ); document.write( "\"12%2F100=k\" Divide both sides by 100 to isolate k\r
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\n" ); document.write( "\n" ); document.write( "\"0.12=k\" Divide\r
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\n" ); document.write( "\n" ); document.write( "So the constant of variation is \"k=0.12\"\r
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\n" ); document.write( "\n" ); document.write( "c)\r
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\n" ); document.write( "\n" ); document.write( "\"p=k%2Aa\" Go back to the earlier equation\r
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\n" ); document.write( "\n" ); document.write( "\"p=0.12%2Aa\" Plug in the constant of variation \"k=0.12\"\r
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\n" ); document.write( "\n" ); document.write( "\"p=0.12%2A2500\" Plug in \"a=2500\"\r
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\n" ); document.write( "\n" ); document.write( "\"p=300\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "So in a 2,500 acre parcel of land, there are 300 deer.\r
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\n" ); document.write( "\n" ); document.write( "By using the equation \"p=0.12%2Aa\" (we needed to solve for k first), we were able to find the number of deer on a given portion of land
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