document.write( "Question 140619: What is the solution set to \"%28x-4%29%2F%28x%2B3%29%3E=2\" \n" ); document.write( "
Algebra.Com's Answer #102344 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"%28x-4%29%2F%28x%2B3%29%3E=2\" Start with the given inequality\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-4%29%2F%28x%2B3%29-2%3E=0\" Subtract 2 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-4%29%2F%28x%2B3%29-%282%29%28x%2B3%29%2F%28x%2B3%29%3E=0\" Multiply 2 by \"%28x%2B3%29%2F%28x%2B3%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-4%29%2F%28x%2B3%29-%282%28x%2B3%29%29%2F%28x%2B3%29%3E=0\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-4-2%28x%2B3%29%29%2F%28x%2B3%29%3E=0\" Combine the fractions\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-4-2x-6%29%2F%28x%2B3%29%3E=0\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"%28-x-10%29%2F%28x%2B3%29%3E=0\" Combine like terms\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B3=0\" Set the denominator equal to zero\r
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\n" ); document.write( "\n" ); document.write( "\"x=0-3\"Subtract 3 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"x=-3\" Combine like terms on the right side\r
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\n" ); document.write( "\n" ); document.write( "So the vertical asymptote is \"x=-3\". So one critical value is \"x=-3\"\r
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\n" ); document.write( "\n" ); document.write( "\"-x-10=0\" Set the numerator equal to zero\r
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\n" ); document.write( "\n" ); document.write( "\"-10=x\" Add x to both sides\r
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\n" ); document.write( "\n" ); document.write( "So another critical value is \"x=-10\"\r
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\n" ); document.write( "\n" ); document.write( "So our critical values are \"x=-3\" and \"x=-10\" \r
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\n" ); document.write( "\n" ); document.write( "Now set up a number line and plot the critical values on the number line\r
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\n" ); document.write( "\n" ); document.write( "\"number_line%28+600%2C+-15%2C+10%2C-3%2C-10%29\"\r
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\n" ); document.write( "\n" ); document.write( "So let's pick some test points that are near the critical values and evaluate them.\r
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\n" ); document.write( "\n" ); document.write( "Let's pick a test value that is less than \"-10\" (notice how it's to the left of the leftmost endpoint):\r
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\n" ); document.write( "\n" ); document.write( "So let's pick \"x=-11\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-4%29%2F%28x%2B3%29%3E=2\" Start with the given inequality\r
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\n" ); document.write( "\n" ); document.write( "\"%28-11-4%29%2F%28-11%2B3%29%3E=+2\" Plug in \"x=-11\"\r
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\n" ); document.write( "\n" ); document.write( "\"1.875%3E=2\" Evaluate and simplify the left side\r
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\n" ); document.write( "\n" ); document.write( "Since the inequality is false, this means that the interval does not work. So this interval is not in our solution set and we can ignore it.\r
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\n" ); document.write( "\n" ); document.write( "Let's pick a test value that is in between \"-10\" and \"-3\":\r
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\n" ); document.write( "\n" ); document.write( "So let's pick \"x=-6\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-4%29%2F%28x%2B3%29%3E=2\" Start with the given inequality\r
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\n" ); document.write( "\n" ); document.write( "\"%28-6-4%29%2F%28-6%2B3%29%3E=+2\" Plug in \"x=-6\"\r
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\n" ); document.write( "\n" ); document.write( "\"3.3333%3E=+2\" Evaluate and simplify the left side\r
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\n" ); document.write( "\n" ); document.write( "Since the inequality is true, this means that the interval works. So this tells us that this interval is in our solution set.\r
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\n" ); document.write( "\n" ); document.write( " So part our solution in interval notation is [)\r
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\n" ); document.write( "\n" ); document.write( "Let's pick a test value that is greater than \"-3\" (notice how it's to the right of the rightmost endpoint):\r
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\n" ); document.write( "\n" ); document.write( "So let's pick \"x=-2\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-4%29%2F%28x%2B3%29%3E=2\" Start with the given inequality\r
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\n" ); document.write( "\n" ); document.write( "\"%28-2-4%29%2F%28-2%2B3%29%3E=+2\" Plug in \"x=-2\"\r
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\n" ); document.write( "\n" ); document.write( "\"-6%3E=+2\" Evaluate and simplify the left side\r
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\n" ); document.write( "\n" ); document.write( "Since the inequality is false, this means that the interval does not work. So this interval is not in our solution set and we can ignore it.\r
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\n" ); document.write( "\n" ); document.write( "Summary:\r
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\n" ); document.write( "\n" ); document.write( "So the solution interval notation is:\r
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\n" ); document.write( "\n" ); document.write( " [)\r
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