document.write( "Question 140597: The perimeter of the rectangle is 190 inches. The length exceeeds the width by 53 inches. Find the length and the width. \r
\n" ); document.write( "\n" ); document.write( "Can someone please help with this one please? The perimeter is the 190 diveded by 4? Is that the way to start or not? \n" ); document.write( "
Algebra.Com's Answer #102329 by jojo14344(1513)\"\" \"About 
You can put this solution on YOUR website!
Dividing the perimeter by 4? You have percentage of being right but not really the way to start it.
\n" ); document.write( "Okay,let's get the formula for perimeter first (P) = 2(L+W), right? This is equation 1.
\n" ); document.write( "Knowing the length(L) exceeds the width(W) by 53, so L=W+53, right? and mark this equation 2. Substitute this value to the 1st eq'n knowing the perimeter:
\n" ); document.write( "190=2(W+53+W)=2(2W+53)=4W+106
\n" ); document.write( "190-106=4W
\n" ); document.write( "84/4=W
\n" ); document.write( "21inches=Width
\n" ); document.write( "Go back eq'n 2: L=21+53
\n" ); document.write( " L=74 inches.
\n" ); document.write( "Simply to check if in doubt,
\n" ); document.write( "P=2(L+W)
\n" ); document.write( "190=2(21+74)=2(95)
\n" ); document.write( "190=190 cool!
\n" ); document.write( "thank you,
\n" ); document.write( "Jojo
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