document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=140368>Question 140368</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A life saver has a 3cm diameter, a 1cm diamter hole and has 1/2 cm height.  Find the volume and total surface area of the life saver.  (Just like the candy lifesaver) That is what the pic looks like.\r<BR>\n" );
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document.write( "Thankyou Shelly </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #102306 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=102306\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A life saver has a 3 cm diameter, a 1 cm diameter hole and has 1/2 cm height. Find the volume and total surface area of the life saver. (Just like the candy lifesaver) That is what the pic looks like. <BR>\n" );
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document.write( "The approach to this problem:<BR>\n" );
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document.write( "Use the volume (V1) of a cylinder (V=pi*r^2*h) to find the volume if it did not have a hole<BR>\n" );
document.write( "Then find the volume (V2)of the material removed to form the hole, also a cylinder. Subtract V2 from V1<BR>\n" );
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document.write( "r = 1.5; h = .5<BR>\n" );
document.write( "V1 = pi*1.5^2*.5<BR>\n" );
document.write( "V1 = 3.5343 cu/cm<BR>\n" );
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document.write( "r = .5; h = .5<BR>\n" );
document.write( "V2 = pi*.5^2*.5<BR>\n" );
document.write( "V2 = .3927 cu/cm<BR>\n" );
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document.write( "3.5343 - .3927 = 3.1416 cu/cm is the volume of the life saver<BR>\n" );
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document.write( "Surface area approach:<BR>\n" );
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document.write( "Find the surface area of a cylinder, ignoring the hole.<BR>\n" );
document.write( "Find area of the 2 circles that form the hole. Subtract from the total surface area.<BR>\n" );
document.write( "Find the area of the sides of the cylinder forming the hole. Add to above area<BR>\n" );
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document.write( "Surface area, ignoring the hole<BR>\n" );
document.write( "r = 1.5, d = 3, h = .5<BR>\n" );
document.write( "SA = 2(pi*1.5^2) + (pi*3*.5) <BR>\n" );
document.write( "SA = 14.1371 + 4.7124<BR>\n" );
document.write( "SA = 18.8495 sq/cm<BR>\n" );
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document.write( "Area of the 2 circles that form the hole<BR>\n" );
document.write( "A = (pi*.5^2) * 2<BR>\n" );
document.write( "A = 1.5708 sq/cm<BR>\n" );
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document.write( "18.8495 - 1.5708 = 17.2787 sq/cm, surface area not including the inside of the hole <BR>\n" );
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document.write( "Find the area of the sides inside the hole: d = 1; h = .5, add to the SA<BR>\n" );
document.write( "A = pi*1*.5<BR>\n" );
document.write( "A = 1.5708<BR>\n" );
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document.write( "Find total surface area:<BR>\n" );
document.write( " 17.2787 + 1.5708 = 18.8495 sq/cm, total surface area.<BR>\n" );
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document.write( "Did this makes sense, by the way what happens to the candy removed from the life saver to form the hole?<BR>\n" );
document.write( "I know that with donuts, you can buy donut holes at the bakery here.<BR>\n" );
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document.write( "I'm sure, Shelly, these comments, interest you tremendously, hope this helps anyway. </SPAN>\n" );
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