document.write( "Question 140417: A cahshier had to give sarah $3.45 in change but he had only quarters and dimes in the register. If he gave her 15 coins, how many dimes did she recieve? \n" ); document.write( "
Algebra.Com's Answer #102288 by jojo14344(1513)![]() ![]() ![]() You can put this solution on YOUR website! First, let us assign \"x\"= # of quarters and \"y\"= # of dimes. \n" ); document.write( "As per given, total # of quarters and dimes given equals 15. To show, \n" ); document.write( "x+y=15, right? Remember this as equation 1. \n" ); document.write( "Now,when we multiply quarter(0.25) by the # of coins \"x\" plus dimes(0.10) multiplied by # of coins \"y\" we get $3.45 as the total change right? To show, \n" ); document.write( "0.25x+0.10y=$3.45, remember this as equation 2 now. \n" ); document.write( "Go back to equation 1, we get y=15-x. Then substitue this value of y to equation 2. To show, \n" ); document.write( "0.25x+0.10(15-x)=$3.45 \n" ); document.write( "0.25x+1.5-0.10x=$3.45 \n" ); document.write( "0.15x=3.45-1.5 \n" ); document.write( "x=13, this will the # of quarters \n" ); document.write( "For the # of dimes, \n" ); document.write( "y=15-x=15-13 \n" ); document.write( "y=2 (# of dimes) \n" ); document.write( "Simply to check refer to equation 2, \n" ); document.write( "0.25(13)+0.10(2)=$3.45 \n" ); document.write( "$3.25+$0.20=$3.45 \n" ); document.write( "$3.45=$3.45 \n" ); document.write( "Cool!\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |