document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=140483>Question 140483</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do you reduce a fraction? i can't do the steps.\r<BR>\n" );
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document.write( "(63/6)(48/7) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #102287 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=102287\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (63/6)(48/7)<BR>\n" );
document.write( "You have to mentally or on paper factor the numbers.\r<BR>\n" );
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document.write( "= (7*3^2/2*3)(3*4^2/7)\r<BR>\n" );
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document.write( "Then you have to find factors that are common to numerator and denominator<BR>\n" );
document.write( "like 3 and 7; cancel these because (3/3)= 1 and 7/7 = 1<BR>\n" );
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document.write( "= (3/2)(3*2^4/1)\r<BR>\n" );
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document.write( "If you missed some common factor on the 1st go round do it again.<BR>\n" );
document.write( "Cancel the common \"2\" that is in the numerator and the denominator:\r<BR>\n" );
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document.write( "= (3/1)(3*2^3/1)\r<BR>\n" );
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document.write( "When there is no more canceling to do, simplify the result:\r<BR>\n" );
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document.write( "= 9*8 = 72<BR>\n" );
document.write( "=================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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