document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=140410>Question 140410</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how would I write an equation using: slope=1/3,passing through(-1,5)? thank you!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #102263 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=102263\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> write an equation using: slope=1/3,passing through(-1,5)<BR>\n" );
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document.write( "form y = mx + b<BR>\n" );
document.write( "You know y=5 when x=-1 and you know m = 1/3; solve for \"b\":\r<BR>\n" );
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document.write( "5 = (1/3)*(-1) + b<BR>\n" );
document.write( "5 = -1/3 + b<BR>\n" );
document.write( "b = 16/3<BR>\n" );
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document.write( "EQUATION:<BR>\n" );
document.write( "y = (1/3)x + (16/3)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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