document.write( "Question 21260: Mr. Jackons is 13 years less than 3 times as old as his son. six years ago he was 14 years more than twice as old as his son was then. Find thire age \n" ); document.write( "
Algebra.Com's Answer #10225 by Paul(988)\"\" \"About 
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3x-13=-6+14+2x
\n" ); document.write( "3x-13=8+2x
\n" ); document.write( "3x-13+13=8+13+2x
\n" ); document.write( "3x=21+2x
\n" ); document.write( "3x-2x=21+2x-2x
\n" ); document.write( "x=21
\n" ); document.write( "3(21)-13=50
\n" ); document.write( "Hence his son is 21 and he is 50
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