document.write( "Question 21260: Mr. Jackons is 13 years less than 3 times as old as his son. six years ago he was 14 years more than twice as old as his son was then. Find thire age \n" ); document.write( "
Algebra.Com's Answer #10225 by Paul(988)![]() ![]() ![]() You can put this solution on YOUR website! 3x-13=-6+14+2x \n" ); document.write( "3x-13=8+2x \n" ); document.write( "3x-13+13=8+13+2x \n" ); document.write( "3x=21+2x \n" ); document.write( "3x-2x=21+2x-2x \n" ); document.write( "x=21 \n" ); document.write( "3(21)-13=50 \n" ); document.write( "Hence his son is 21 and he is 50 \n" ); document.write( " |