document.write( "Question 21252: If the rectangle's width is tripled and its length is doubled, the perimeter of the new rectangle is 92cm greater than the original perimeter.
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document.write( " What is the area of the original rectangle.\r
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document.write( "^^how in the world would i solve this??? if its possible i would prefer for the answer not to be given but it doesnt matter.^^ \n" );
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Algebra.Com's Answer #10224 by Photonjohn(42) ![]() You can put this solution on YOUR website! Area = Length x Width = L x W \n" ); document.write( "but 2L x 3W = Area + 92 \n" ); document.write( "so 6LW = Area + 92 \n" ); document.write( "6 x Area = Area + 92 \n" ); document.write( "5 x Area = 92 \n" ); document.write( "Solve for Area... \n" ); document.write( " |