document.write( "Question 140352: 9x+4y=-17
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document.write( "12y=-3-3x
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document.write( "using substition or elimination \n" );
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Algebra.Com's Answer #102213 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! 9x+4y=-17-----------------eq1 \n" ); document.write( "12y=-3-3x -----------------eq2\r \n" ); document.write( "\n" ); document.write( "divide each term in eq2 by 3\r \n" ); document.write( "\n" ); document.write( "4y=-1-x--------------------eq2a\r \n" ); document.write( "\n" ); document.write( "Now substitute 4y=-1-x from eq2a into eq1:\r \n" ); document.write( "\n" ); document.write( "9x-1-x=-17 add 1 to each side\r \n" ); document.write( "\n" ); document.write( "9x-1+1-x=-17+1 collect like terms\r \n" ); document.write( "\n" ); document.write( "8x=-16 divide each side by 8 \n" ); document.write( "x=-2--substitute this into eq2a\r \n" ); document.write( "\n" ); document.write( "4y=-1+2=1 divide each side by 4\r \n" ); document.write( "\n" ); document.write( "y=1/4\r \n" ); document.write( "\n" ); document.write( "CK \n" ); document.write( "From eq1: \n" ); document.write( "9*(-2)+4(1/4)=-17 \n" ); document.write( "-18+1=-17 \n" ); document.write( "-17=-17 \n" ); document.write( "From eq2a \n" ); document.write( "4(1/4)=-1+2 \n" ); document.write( "1=1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( " |