document.write( "Question 140236This question is from textbook
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document.write( ": A oicture frame measures 12cm by 20cm. 84cm(squared) of picture shows inside the frame. Find the width of frame \n" );
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Algebra.Com's Answer #102212 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A picture frame measures 12 cm by 20 cm. 84 cm(squared) of picture shows inside the frame. Find the width of frame \n" ); document.write( ": \n" ); document.write( "Let x = width of the frame \n" ); document.write( ": \n" ); document.write( "then the dimension of the picture would be: (20-2x) by (12-2x) \n" ); document.write( ": \n" ); document.write( "The area of the picture: \n" ); document.write( "(20-2x)*(12-2x) = 84 \n" ); document.write( "FOIL \n" ); document.write( "240 - 40x - 24x + 4x^2 = 84 \n" ); document.write( "Arrange as a quadratic equation: \n" ); document.write( "4x^2 - 64x + 240 - 84 = 0 \n" ); document.write( ": \n" ); document.write( "4x^2 - 64x + 156 = 0 \n" ); document.write( ": \n" ); document.write( "Simplify, divide by 4: \n" ); document.write( "x^2 - 16x + 39 = 0 \n" ); document.write( "Factor \n" ); document.write( "(x-13)(x-3) = 0 \n" ); document.write( ": \n" ); document.write( "Two solutions, however, \n" ); document.write( "x = +3 cm; is the only one that makes sense. \n" ); document.write( ": \n" ); document.write( "Width of the frame: 12 - 2(3) = 6 cm \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution by finding the area using the picture dimensions: L = 20-2(3) = 14 \n" ); document.write( "14 * 6 = 84 sq/cm as given \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "did I make sense to you here? Let me know, please. \n" ); document.write( " |