document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=140310>Question 140310</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have a worksheet that states if angle 1 and angle2 are complementary angles and m alngle 1=5x-9 and m angle 2=4x, find the measure of the two angles.\r<BR>\n" );
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document.write( "I'm not sure if it is right, but i went:  (5x-9)+(4x)=90<BR>\n" );
document.write( "                                          5x+4x-9=90<BR>\n" );
document.write( "                                           9x-9=180<BR>\n" );
document.write( "                                             +9 +9<BR>\n" );
document.write( "                                            9x=99<BR>\n" );
document.write( "                                           9x/9 =99/9<BR>\n" );
document.write( "                                            x= 11\r<BR>\n" );
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document.write( "the next one i had a question on said: in the figure AB and CD are parallel lines cut by transversal EF.  If m angle AEF =47, find m angle DFE.\r<BR>\n" );
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document.write( "I did:  m anlge AEF = m angle DFE = 180<BR>\n" );
document.write( "         47 + m angle DFE =180<BR>\n" );
document.write( "         -47              -47<BR>\n" );
document.write( "            m angle DFE = 133<BR>\n" );
document.write( "                  <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #102183 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=102183\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I) If two angles (5x-9) and (4x) are complementary, their sum is 90 degrees.<BR>\n" );
document.write( "(5x-9)+4x = 90<BR>\n" );
document.write( "9x-9 = 90<BR>\n" );
document.write( "9x = 99 Divide both sides by 9<BR>\n" );
document.write( "x = 11<BR>\n" );
document.write( "Angle 1:<BR>\n" );
document.write( "5x-9 = 5(11)-9 = 55-9 = 46<BR>\n" );
document.write( "Angle 1 is 46 degrees.<BR>\n" );
document.write( "Angle 2:<BR>\n" );
document.write( "4x = 4(11) = 44<BR>\n" );
document.write( "Angle 2 = 44 degrees.<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "46+44 = 90<BR>\n" );
document.write( "II) The best I can figure out without the actual diagram is that the two angles in your problem  AEF and DFE, are alternate interior angles, and alternate interior angles are congruent (equal). </SPAN>\n" );
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