document.write( "Question 140313: Graph the equation \"%28x-2%29%5E2%2B%28y%2B1%29%5E2=12\"\r
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Algebra.Com's Answer #102182 by jim_thompson5910(35256)\"\" \"About 
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\"%28x-2%29%5E2%2B%28y%2B1%29%5E2=12\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"%28y%2B1%29%5E2=12-%28x-2%29%5E2\" Subtract \"%28x-2%29%5E2\" from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"y%2B1=0%2B-sqrt%2812-%28x-2%29%5E2%29\" Take the square root of both sides\r
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\n" ); document.write( "\n" ); document.write( "\"y=0%2B-sqrt%2812-%28x-2%29%5E2%29-1\" Subtract 1 from both sides\r
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\n" ); document.write( "\n" ); document.write( "So we have the two equations \r
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\n" ); document.write( "\n" ); document.write( "\"y=sqrt%2812-%28x-2%29%5E2%29-1\" and \"y=-sqrt%2812-%28x-2%29%5E2%29-1\"\r
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\n" ); document.write( "\n" ); document.write( "So when we graph the two equations we get\r
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\n" ); document.write( "\n" ); document.write( " Graph of \"y=sqrt%2812-%28x-2%29%5E2%29-1\" (red) and \"y=-sqrt%2812-%28x-2%29%5E2%29-1\" (green)
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