document.write( "Question 140268: In order to test whether marathon races are bad for health, a researcher took a random sample of 400 runners who participated in the New York half marathon, and found that 13% of them got sick in the two-week period after the marathon. In a second sample of 400 runners who did not participate in the marathon, only 3% were sick in the same two week period. What would be the null hypothesis? Find a 90% confidence interval for the percentage of New York half marathon runners who got sick in the two weeks after the race.\r
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\n" ); document.write( "\n" ); document.write( "PLS pls help, I am only a student in long distance education and need help to solve exam problems. This is from my question paper
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Algebra.Com's Answer #102168 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
In order to test whether marathon races are bad for health, a researcher took a random sample of 400 runners who participated in the New York half marathon, and found that 13% of them got sick in the two-week period after the marathon. In a second sample of 400 runners who did not participate in the marathon, only 3% were sick in the same two week period. What would be the null hypothesis? Find a 90% confidence interval for the percentage of New York half marathon runners who got sick in the two weeks after the race.
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\n" ); document.write( "1st sample:
\n" ); document.write( "n1=400
\n" ); document.write( "p-hat = 0.13
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\n" ); document.write( "2nd sample:
\n" ); document.write( "n2=400
\n" ); document.write( "p-hat = 0.03
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\n" ); document.write( "Ho: p1 - p2 = 0
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\n" ); document.write( "Confidence Interval
\n" ); document.write( "p1-hat - p2-hat = 0.10
\n" ); document.write( "E = 1.645*sqrt[(0.13*0.87/400) + (0.03*0.97)/400)] = 0.031016
\n" ); document.write( "90% CI: 0.1-0.031016 < p < 0.1 + 0.31016
\n" ); document.write( "= 0.68984 < p < 1.31016\r
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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