document.write( "Question 140241: x^2+4x+1=0 \n" ); document.write( "

Algebra.Com's Answer #102145 by checkley77(12844) $\"\"$ $\"About$

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x^2+4x+1=0
\n" ); document.write( "Using the uadratic equation: $\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"$ we get:
\n" ); document.write( "x=(-4+-sqrt4^2-4*1*1])/2*1
\n" ); document.write( "x=(-4+-sqrt[16-4])/2
\n" ); document.write( "x=(-4+-sqrt12)/2
\n" ); document.write( "x=(-4+-3.464)/2
\n" ); document.write( "x=(-4+3.464)/2
\n" ); document.write( "x=-.536/2
\n" ); document.write( "x=-.268 answer.
\n" ); document.write( "x=(-4-3.464)/2
\n" ); document.write( "x=-7.464/2
\n" ); document.write( "x=-3.732 answer. \n" ); document.write( "

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