document.write( "Question 140225: I have a rather detailed problem, could I please have some help solving.
\n" ); document.write( "Thank you. The length of a rectangle is 8ft longer than its width, which is the same dimension as the side of a square. If the area of the rectangle is equal to 160 square feet more than the area of the square, what are the length and width of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #102144 by ankor@dixie-net.com(22740)\"\" \"About 
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The length of a rectangle is 8ft longer than its width, which is the same dimension as the side of a square. If the area of the rectangle is equal to 160 square feet more than the area of the square, what are the length and width of the rectangle?
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\n" ); document.write( "Let x = width of the rectangle and the length of the side of the square
\n" ); document.write( "Then
\n" ); document.write( "(x+8) = length of the rectangle
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\n" ); document.write( "Rectangle area - square area = 160 sq/ft
\n" ); document.write( "x(x+8) - x^2 = 160
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\n" ); document.write( "x^2 + 8x - x^2 = 160
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\n" ); document.write( "8x = 160
\n" ); document.write( "x =\"160%2F8\"
\n" ); document.write( "x = 20 ft is the width, that makes the length 28 ft
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\n" ); document.write( "Check solution by finding the areas
\n" ); document.write( "28 * 20 = 560
\n" ); document.write( "20 * 20 = 400
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\n" ); document.write( "difference160; confirms our solution \n" ); document.write( "
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