document.write( "Question 140230: I have a problem that I wanted to check to see if I've figured out the right answer. The hypotenuse of a right triangle is 4 inches long. one leg is 1 inch longer than the other. Find the length of the shorter leg to the nearest tenth.
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document.write( "I have 2.3 is this right. Want to make sure I'm understanding the problem correctly. Thank you. \n" );
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Algebra.Com's Answer #102142 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! 4^2=x^2+(x+1)^2 \n" ); document.write( "16=x^2+x^2+2x+1 \n" ); document.write( "2x^2+2x+1-16=0 \n" ); document.write( "2x^2+2x-15=0 \n" ); document.write( "Using the quadratic equation: \n" ); document.write( "x=(-2+-sqrt[-2^2-4*2*-15])/2*2 \n" ); document.write( "x=(-2+-sqrt[4+120])/4 \n" ); document.write( "x=(-2+-sqrt124)/4 \n" ); document.write( "x=(-2+-11.1355)/4 \n" ); document.write( "x=(-2+11.1355)/4 \n" ); document.write( "x=9.1355)/4 \n" ); document.write( "x=2.28 for the shorter leg. \n" ); document.write( "2.28+1=3.28 for the longer leg. \n" ); document.write( "proof \n" ); document.write( "16=2.28^2+3.28^2 \n" ); document.write( "16=5.2+10.8 \n" ); document.write( "16=16 \n" ); document.write( " \n" ); document.write( " |