document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=140200>Question 140200</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Chords, radius and diameter<BR>\n" );
document.write( "  Given: chord lenght=16<BR>\n" );
document.write( "         a line from the center to the chord=6<BR>\n" );
document.write( "         What is the formula to find the diameter?<BR>\n" );
document.write( "Thanks...Kayley </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #102140 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=102140\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if the line is from the center of the circle to the center of the chord...it is a perpendicular bisector\r<BR>\n" );
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document.write( "the line, half the chord, and the radius form a right triangle; with the radius as the hypotenuse\r<BR>\n" );
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document.write( "so 6^2+(16/2)^2=r^2 __ 36+64=r^2 __ 10=r\r<BR>\n" );
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document.write( "if the radius is 10, then the diameter is 20 </SPAN>\n" );
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