document.write( "Question 140168: two consecutive odd integers such that 55 more than 5 times their sum is equal to their product. \n" ); document.write( "
Algebra.Com's Answer #102133 by ankor@dixie-net.com(22740)\"\" \"About 
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:
\n" ); document.write( "Let the two consecutive odd integers = x, (x+2)
\n" ); document.write( ":
\n" ); document.write( "Write an equation for the statement:
\n" ); document.write( "\"two consecutive odd integers such that 55 more than 5 times their sum is equal to their product.\"
\n" ); document.write( "5(x + (x+2)) + 55 = x(x+2}
\n" ); document.write( ":
\n" ); document.write( "5(2x+2) + 55 = x^2 + 2x
\n" ); document.write( ":
\n" ); document.write( "10x + 10 + 55 = x^2 + 2x
\n" ); document.write( ":
\n" ); document.write( "10x + 65 = x^2 + 2x
\n" ); document.write( "Arrange it as a quadratic equation:
\n" ); document.write( "x^2 + 2x - 10x - 65 = 0
\n" ); document.write( ";
\n" ); document.write( "x^2 - 8x - 65 = 0
\n" ); document.write( "Factor to
\n" ); document.write( "(x-13)(x+5) = 0
\n" ); document.write( "Two solutions:
\n" ); document.write( "x = 135(x + (x+2) + 55 = x(x+2}
\n" ); document.write( "x = -5
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check for consecutive odd integers: -5 and -3 in the original equation
\n" ); document.write( "5(-5 + (-3)) + 55 = -5(-3}
\n" ); document.write( "5(-8) + 55 = +15
\n" ); document.write( ":
\n" ); document.write( "You can check it for x = +13 \n" ); document.write( "
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