document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=140140>Question 140140</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of a number and 25 times its reciprocal is 10. Find the number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #102096 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=102096\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=the number<BR>\n" );
document.write( "then 1/x is the reciprocal<BR>\n" );
document.write( "25 times the reciprocal is:<BR>\n" );
document.write( "25/x\r<BR>\n" );
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document.write( "Now we are told that x+(25/x)=10  multiply each term by x<BR>\n" );
document.write( "x^2+25=10x  subtract 10x from each side\r<BR>\n" );
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document.write( "x^2-10x+25=10x-10x or<BR>\n" );
document.write( "x^2-10x+25=0----quadratic in standard form and it can be factored<BR>\n" );
document.write( "(x-5)^2=0 take sqrt of both sides<BR>\n" );
document.write( "x-5=0<BR>\n" );
document.write( "x=5\r<BR>\n" );
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document.write( "CK<BR>\n" );
document.write( "5+25/5=10<BR>\n" );
document.write( "10=10\r<BR>\n" );
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document.write( "Hope this helps---ptaylor<BR>\n" );
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