document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=140143>Question 140143</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Elizabeth drove to Thomas' house at 57 mph.Thomas' house is seventy-one miles away.Elizabeth arrived at Thomas' house at 4:27 p.m. What time did she leave? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #102095 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=102095\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r\r<BR>\n" );
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document.write( "Let t=amount of time required for Elizabeth to make the trip to Thomas' house\r<BR>\n" );
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document.write( "Now we know that t=d/r=71/57; t=1.25 hrs or 1 hr 15min\r<BR>\n" );
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document.write( "So 4:27 p.m. minus 1hr 15min=3:12 p.m.\r<BR>\n" );
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document.write( "Hope this helps---ptaylor </SPAN>\n" );
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