document.write( "Question 140048: I pick up 3 cards from a standard deck, one after another, keeping each card that I pick (without replacement) What is the probability that as least 2 of the 3 cards are the same suit?\r
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document.write( "B) There are 10 cards in a hat, 4 red and the rest black. You pull out 2 cards without looking. What is the probability that they are the same color? Would this be (Prob of red)= 4/10*3/9+(Prob of all black) 6/10*5/9=42/90= 46% \n" );
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Algebra.Com's Answer #102079 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! I pick up 3 cards from a standard deck, one after another, keeping each card that I pick (without replacement) What is the probability that as least 2 of the 3 cards are the same suit? \n" ); document.write( "Prob(2 or 3 are the same suit) = 1 - P(none are the same suit) \n" ); document.write( "Prob(none) = ? \n" ); document.write( "1st: pick any card (52/52) \n" ); document.write( "2nd: pick a card not of that suit (39/51) \n" ); document.write( "3rd: pick a card of neither picked suit (26/50) \n" ); document.write( "Therefore ? = 1 - (39/51)(26/50) = 1-0.39765... = 0.6024.. \n" ); document.write( "=======================\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "B) There are 10 cards in a hat, 4 red and the rest black. You pull out 2 cards without looking. What is the probability that they are the same color? Would this be (Prob of red)= 4/10*3/9+(Prob of all black) 6/10*5/9=42/90= 46% \n" ); document.write( "------ \n" ); document.write( "P(2 red or 2 black) = [4C2+6C2]/10C2 = [6 + 15]/45 = 21/45 \n" ); document.write( "============ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------------------ \n" ); document.write( " |