document.write( "Question 140017: 1. The perimeter of a rectangular box is 42 inches. The length of the box is 15 inches
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document.write( " more than the width. Determine the dimensions of the rectangle in terms of feet
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document.write( " Also find the area of the box in terms of feet. Draw the diagram by showing the
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document.write( " dimensions.
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document.write( " (a) How will you set up the problem.
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document.write( " (b) What are the two linear equations.
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document.write( " (c) What is the product of two dimensions of the rectangle.
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document.write( " (d) How is this product different from perimeter. Interpret on that.
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Algebra.Com's Answer #102045 by jim_thompson5910(35256) ![]() You can put this solution on YOUR website! a) \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let L=length, W=width\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "b)\r \n" ); document.write( "\n" ); document.write( "Since \"The length of the box is 15 inches more than the width\", this means the first equation is \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Remember the perimeter formula is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If we plug in \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the two equations are:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "c) the product of the two dimensions of the rectangle is \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "d) The perimeter is a linear equation while the product is a nonlinear equation \n" ); document.write( " |