document.write( "Question 140017: 1. The perimeter of a rectangular box is 42 inches. The length of the box is 15 inches
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\n" ); document.write( " Also find the area of the box in terms of feet. Draw the diagram by showing the
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\n" ); document.write( " (a) How will you set up the problem.
\n" ); document.write( " (b) What are the two linear equations.
\n" ); document.write( " (c) What is the product of two dimensions of the rectangle.
\n" ); document.write( " (d) How is this product different from perimeter. Interpret on that.
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Algebra.Com's Answer #102045 by jim_thompson5910(35256)\"\" \"About 
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a) \r
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\n" ); document.write( "\n" ); document.write( "Let L=length, W=width\r
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\n" ); document.write( "\n" ); document.write( "b)\r
\n" ); document.write( "\n" ); document.write( "Since \"The length of the box is 15 inches more than the width\", this means the first equation is \"L=W%2B15\"\r
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\n" ); document.write( "\n" ); document.write( "Remember the perimeter formula is \"P=2%2AW%2B2%2AL\"\r
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\n" ); document.write( "\n" ); document.write( "If we plug in \"P=42\", we get the second equation: \r
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\n" ); document.write( "\n" ); document.write( "\"42=2%2AW%2B2%2AL\"\r
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\n" ); document.write( "\n" ); document.write( "So the two equations are:\r
\n" ); document.write( "\n" ); document.write( " \"L=W%2B15\"\r
\n" ); document.write( "\n" ); document.write( "\"42=2%2AW%2B2%2AL\"\r
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\n" ); document.write( "\n" ); document.write( "c) the product of the two dimensions of the rectangle is \r
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\n" ); document.write( "\n" ); document.write( "\"W%2AL=W%2A%28W%2B15%29=W%5E2%2B15W\"\r
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\n" ); document.write( "\n" ); document.write( "d) The perimeter is a linear equation while the product is a nonlinear equation
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