document.write( "Question 139969: sample final question...trying to study correctly for final :\r
\n" ); document.write( "\n" ); document.write( "solve each equation:\r
\n" ); document.write( "\n" ); document.write( "log (7x+8) = 2 log x\r
\n" ); document.write( "\n" ); document.write( "THANK U THANK U THANK U \n" ); document.write( "

Algebra.Com's Answer #102032 by Earlsdon(6294) $\"\"$ $\"About$

You can put this solution on YOUR website!
Solve for x:
\n" ); document.write( " $\"log%28%287x%2B8%29%29+=+2%2Alog%28%28x%29%29\"$ Apply the power rule to the right side.
\n" ); document.write( " $\"log%28%287x%2B8%29%29+=+log%28%28x%5E2%29%29\"$ Now, if $\"Log%5Bb%5D%28M%29+=+Log%5Bb%5D%28N%29\"$ then $\"M+=+N\"$ , so...
\n" ); document.write( " $\"7x%2B8+=+x%5E2\"$ Subtract 7x+8 from both sides.
\n" ); document.write( " $\"x%5E2-7x-8+=+0\"$ Factor the trinomial.
\n" ); document.write( " $\"x%2B1%29%28x-8%29+=+0\"$ Apply the zero product rule:
\n" ); document.write( " $\"x%2B1+=+0\"$ or $\"x-8+=+0\"$ , so...
\n" ); document.write( " $\"x+=+-1\"$ or $\"x+=+8\"$ \n" ); document.write( "

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