document.write( "Question 139973: I NEED HELP....THIS IS THE LAST ONE TROUBLING ME....STUDYING FOR FINAL:\r
\n" ); document.write( "\n" ); document.write( "write as single logarithm:
\n" ); document.write( "-2 log base3 (1/x) + 1/3 log base3 square rt(x)\r
\n" ); document.write( "\n" ); document.write( "APPRECIATE ALL YOU ALL DO..THIS IS A LIFE SAVER WHAT YA'LL ARE DOING TO HELP...THANKS SO MUCH!!! \n" ); document.write( "

Algebra.Com's Answer #102031 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

You can put this solution on YOUR website!
-2 log base3 (1/x) + 1/3 log base3 square rt(x)
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\n" ); document.write( "rewrite using exponents, the reciprocal gets rid of the negative:
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\n" ); document.write( "logb3(x^2) + (1/3)*logb3(x^(1/2)); note that the $\"sqrt%28x%29\"$ = x^(1/2)
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\n" ); document.write( "logb3(x^2) + logb3(x^(1/6)); multiply the exponents 1/3*1/2
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\n" ); document.write( "Plus means multiply, add exponents: (2 + 1/6 = 12/6 + 1/6)
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\n" ); document.write( "logb3(x^2*x^1/6)) = logb3(x^(13/6))
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