document.write( "Question 139970: A is directly proportional to B. When A is 7, B is 2. What is B when A is 10?
\n" ); document.write( "P is inversely proportional to Q. P is 5 when Q is (1/10). What is P when Q is 0.01?\r
\n" ); document.write( "\n" ); document.write( "I am confused? Do you set this up as a cross multiplication? Please help. Thankyou Bill
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Algebra.Com's Answer #102027 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
A is directly proportional to B.
\n" ); document.write( "A = kB
\n" ); document.write( "----------
\n" ); document.write( "When A is 7, B is 2.
\n" ); document.write( "Use this information to solve for \"k\":
\n" ); document.write( "7 = k*2
\n" ); document.write( "k = 7/2
\n" ); document.write( "----------------
\n" ); document.write( "Therefore the equations that relates A and B is A = (7/2)B
\n" ); document.write( "What is B when A is 10?
\n" ); document.write( "10 = (7/2)B
\n" ); document.write( "B = 20/7
\n" ); document.write( "===========================
\n" ); document.write( "Next Problem:\r
\n" ); document.write( "\n" ); document.write( "P is inversely proportional to Q
\n" ); document.write( "P = k/Q
\n" ); document.write( "--------------
\n" ); document.write( "P is 5 when Q is (1/10)
\n" ); document.write( "5 = k/(1/10)
\n" ); document.write( "k = 1/2
\n" ); document.write( "--------
\n" ); document.write( "EQUATION:
\n" ); document.write( "P = 1/(2Q)
\n" ); document.write( "What is P when Q is 0.01?
\n" ); document.write( "P = 1/(0.02)
\n" ); document.write( "P = 50
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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