document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=139860>Question 139860</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1.) ? KL = 300 L\r<BR>\n" );
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document.write( "PLZ help me thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #101959 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=101959\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I would start by writing it the other way:\r<BR>\n" );
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document.write( "300 L = ______ KL\r<BR>\n" );
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document.write( "Since you are converting from smaller to larger unit, move the decimal 3 places to the LEFT.  This would be 0.3 KL.  For additional help with this, please see my Lesson Plan on Metric System in algebra.com, or see it on my own website.  Click on my tutor name 'rapaljer\" anywhere in algebra.com, and look for \"Topics from Geometry.\"  The first link on that page is \"Metric System.\"\r<BR>\n" );
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document.write( "R^2 </SPAN>\n" );
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