document.write( "Question 139871: The sum of three consecutive integers are arranged such that twice the middle integer is equal to 9 more than the largest. What is the sum of the three integers? \n" ); document.write( "
Algebra.Com's Answer #101956 by ankor@dixie-net.com(22740)\"\" \"About 
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Three consecutive integers, x, (x+1), (x+2)
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\n" ); document.write( "The sum of three consecutive integers are arranged such that twice the middle integer is equal to 9 more than the largest.
\n" ); document.write( "2(x+1) = (x+ 2) + 9
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\n" ); document.write( "2x + 2 = x + 11
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\n" ); document.write( "2x - x = 11 - 2
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\n" ); document.write( "x = 9 is the 1st integer
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\n" ); document.write( "What is the sum of the three integers?
\n" ); document.write( "9 + 10 + 11 = 30
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\n" ); document.write( "Check solution in the statement:
\n" ); document.write( "\"twice the middle integer is equal to 9 more than the largest.\"
\n" ); document.write( "2 * 10 = 11 + 9
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