document.write( "Question 139826: A line passing through (-4,4) and (x,-8) is perpendicular to a line with slope 5/12. Find the value of x. \n" ); document.write( "
Algebra.Com's Answer #101940 by ankor@dixie-net.com(22740)\"\" \"About 
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A line passing through (-4,4) and (x,-8) is perpendicular to a line with slope 5/12. Find the value of x.
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\n" ); document.write( "m1 = slope of the given coordinates
\n" ); document.write( "m2 = 5/12
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\n" ); document.write( "We know that the relationship of the slopes of perpendicular lines is:
\n" ); document.write( "m1 * m2 = -1
\n" ); document.write( "m1 *\"5%2F12\" = -1
\n" ); document.write( "Multiply equation by 12:
\n" ); document.write( "m1 * 5 = -12
\n" ); document.write( "m1 = \"-12%2F5\"
\n" ); document.write( ":
\n" ); document.write( "Using the slope formula; (y2-y1)/(x2-x1) = m:
\n" ); document.write( "\"%28-8+-+4%29%2F%28x+-%28-4%29%29\" = \"-12%2F5\"
\n" ); document.write( ":
\n" ); document.write( "You can see that x has to = 1, but here is the algebra to solve it:
\n" ); document.write( "\"%28-12%29%2F%28%28x%2B4%29%29\" = \"-12%2F5\"
\n" ); document.write( "neg on both sides:
\n" ); document.write( "\"12%2F%28%28x%2B4%29%29\" = \"12%2F5\"
\n" ); document.write( "cross multiply, solve for x:
\n" ); document.write( "12(x+4) = 12 * 5
\n" ); document.write( "12x + 48 = 60
\n" ); document.write( "12x = 60 - 48
\n" ); document.write( "12x = 12
\n" ); document.write( "x = 1
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