document.write( "Question 139793: The perimeter of a rectangle is 96 inches. The length exceeds the width by 2 inches. Find the length and width. \n" ); document.write( "
Algebra.Com's Answer #101923 by checkley77(12844)\"\" \"About 
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L=W+2
\n" ); document.write( "2W+2(W+2)=96
\n" ); document.write( "2W+2W+4=96
\n" ); document.write( "4W=96-4
\n" ); document.write( "4W=92
\n" ); document.write( "W=92/4
\n" ); document.write( "W=23IN. ANSWER FOR THE WIDTH.
\n" ); document.write( "L=23+2=25IN. ANSWER FOR THE LENGTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "2*23+2*25=96
\n" ); document.write( "46+50=96
\n" ); document.write( "96=96\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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