document.write( "Question 139678: Tutor could you help me please: A homeowner wants to fence a rectangular garden using 120 ft of fencing. The side of the garage will be used as one side of the rectangle. Find the dimensions for which the area is a maximum.\r
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Algebra.Com's Answer #101824 by stanbon(75887)\"\" \"About 
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Tutor could you help me please: A homeowner wants to fence a rectangular garden using 120 ft of fencing. The side of the garage will be used as one side of the rectangle. Find the dimensions for which the area is a maximum.
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\n" ); document.write( "Draw the picture.
\n" ); document.write( "You have three lengths of fence; two are equal so call them \"x\": one
\n" ); document.write( "is not equal but it can be called 120-2x because it is the rest of
\n" ); document.write( "the fence after you have used up the two x's.
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\n" ); document.write( "EQUATION:
\n" ); document.write( "Area of the rectangle = x*(120-2x) = 120x-2x^2
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\n" ); document.write( "That is a quadratic with a=-2 and b = 120
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\n" ); document.write( "The maximum occurs when x = -b/2a = -120/(2*-2) = 30
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\n" ); document.write( "So the two equal sides are each 30 ft.
\n" ); document.write( "The other side is 120 - 2x = 120 - 2*30 = 60 ft.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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