document.write( "Question 139593This question is from textbook
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\n" ); document.write( "\n" ); document.write( "5x2+16x+3
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Algebra.Com's Answer #101782 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "Looking at \"5x%5E2%2B16x%2B3\" we can see that the first term is \"5x%5E2\" and the last term is \"3\" where the coefficients are 5 and 3 respectively.\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient 5 and the last coefficient 3 to get 15. Now what two numbers multiply to 15 and add to the middle coefficient 16? Let's list all of the factors of 15:\r
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\n" ); document.write( "\n" ); document.write( "Factors of 15:\r
\n" ); document.write( "\n" ); document.write( "1,3,5,15\r
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\n" ); document.write( "\n" ); document.write( "-1,-3,-5,-15 ...List the negative factors as well. This will allow us to find all possible combinations\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to 15\r
\n" ); document.write( "\n" ); document.write( "1*15\r
\n" ); document.write( "\n" ); document.write( "3*5\r
\n" ); document.write( "\n" ); document.write( "(-1)*(-15)\r
\n" ); document.write( "\n" ); document.write( "(-3)*(-5)\r
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\n" ); document.write( "\n" ); document.write( "note: remember two negative numbers multiplied together make a positive number\r
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\n" ); document.write( "\n" ); document.write( "Now which of these pairs add to 16? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 16\r
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First NumberSecond NumberSum
1151+15=16
353+5=8
-1-15-1+(-15)=-16
-3-5-3+(-5)=-8
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\n" ); document.write( "\n" ); document.write( "From this list we can see that 1 and 15 add up to 16 and multiply to 15\r
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\n" ); document.write( "\n" ); document.write( "Now looking at the expression \"5x%5E2%2B16x%2B3\", replace \"16x\" with \"1x%2B15x\" (notice \"1x%2B15x\" adds up to \"16x\". So it is equivalent to \"16x\")\r
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\n" ); document.write( "\n" ); document.write( "\"5x%5E2%2Bhighlight%281x%2B15x%29%2B3\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's factor \"5x%5E2%2B1x%2B15x%2B3\" by grouping:\r
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\n" ); document.write( "\n" ); document.write( "\"%285x%5E2%2B1x%29%2B%2815x%2B3%29\" Group like terms\r
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\n" ); document.write( "\n" ); document.write( "\"x%285x%2B1%29%2B3%285x%2B1%29\" Factor out the GCF of \"x\" out of the first group. Factor out the GCF of \"3\" out of the second group\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B3%29%285x%2B1%29\" Since we have a common term of \"5x%2B1\", we can combine like terms\r
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\n" ); document.write( "\n" ); document.write( "So \"5x%5E2%2B1x%2B15x%2B3\" factors to \"%28x%2B3%29%285x%2B1%29\"\r
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\n" ); document.write( "\n" ); document.write( "So this also means that \"5x%5E2%2B16x%2B3\" factors to \"%28x%2B3%29%285x%2B1%29\" (since \"5x%5E2%2B16x%2B3\" is equivalent to \"5x%5E2%2B1x%2B15x%2B3\")\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"5x%5E2%2B16x%2B3\" factors to \"%28x%2B3%29%285x%2B1%29\" \r
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