document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=139462>Question 139462</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What are the dimensions of a rectangle that has a perimeteer of 42 meters and an area of 90 square meters.\r<BR>\n" );
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document.write( "HELP! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #101754 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=101754\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2L+2W=42<BR>\n" );
document.write( "2L=42-2W<BR>\n" );
document.write( "L=42/2-2W/2<BR>\n" );
document.write( "L=21-W<BR>\n" );
document.write( "LW=90<BR>\n" );
document.write( "(21-W)W=90<BR>\n" );
document.write( "21W-W^2=90<BR>\n" );
document.write( "-W^2+21W-90=0<BR>\n" );
document.write( "W^2-21W+90=0<BR>\n" );
document.write( "(W-15)(W-6)=0<BR>\n" );
document.write( "W-15=0<BR>\n" );
document.write( "W=15 ANSWER.<BR>\n" );
document.write( "W-6=0<BR>\n" );
document.write( "W=6 ANSWER.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "2*6=2*15=42<BR>\n" );
document.write( "12+30=42<BR>\n" );
document.write( "42=42<BR>\n" );
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