document.write( "Question 139510: 3. An investor bought 500 shares of stock , some at $ 3.50 per share and some at $6.00 per share. If the total cost was $ 2187.50, how many shares of each stock did the investor buy?
\n" ); document.write( "(a) How will you set up the problem?
\n" ); document.write( "(b) What is the equation in terms of the variables?
\n" ); document.write( "(c) Which shares are more?
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Algebra.Com's Answer #101746 by frostusna(7)\"\" \"About 
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You have two unknowns, the number of each stock bought, so you need two equations. \r
\n" ); document.write( "\n" ); document.write( "First, let x=number of stock at $3.50 and y=number of stock at $6.00.\r
\n" ); document.write( "\n" ); document.write( "We know that \"x+%2B+y+=+500\"
\n" ); document.write( "and we know \"3.50+%2A+x+%2B+6.00+%2A+y+=+2187.50\"\r
\n" ); document.write( "\n" ); document.write( "Solve the first equation for y: \"y+=+500+-+x\" and substitute this value for y into the second equation.\r
\n" ); document.write( "\n" ); document.write( "\"3.5x+%2B+6%28500+-+x%29+=+2187.50\"
\n" ); document.write( "\"3.5x+%2B+3000+-+6x+=+2187.5\"
\n" ); document.write( "\"3000+-+2.5x+=+2187.5\"
\n" ); document.write( "\"812.5+=+2.5x\"
\n" ); document.write( "\"x+=+325\" the number of $3.50 stocks bought.
\n" ); document.write( "\"y+=+500+-+325+=+175\" the number of $6.00 stocks bought.
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